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42+x^2+43x=0
a = 1; b = 43; c = +42;
Δ = b2-4ac
Δ = 432-4·1·42
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-41}{2*1}=\frac{-84}{2} =-42 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+41}{2*1}=\frac{-2}{2} =-1 $
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